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A road increases 10 m in altitude for every 300 m of its horizontal distance. To the nearest 1/10 of a degree, what is the angle of inclination of the road?

3 years ago

Answered By Qi X

For word problems like this, it is beneficial to start off by drawing a diagram with the given information. The word "altitude" is the same as the word "height" in this context. For every 300 meters of a road's horizontal distance, there is a 10m increase in height.

The angle of inclination of the road is referring to the angle between the "flat" horizontal line, and the diagonal line that represents the tilted road.

 

Based on this diagram, we can see that the 10m side is opposite to the angle. The 300m side is adjacent to the angle. Using the trigonometry rule of SOHCAHTOA, we know that the tangent of an angle equals the opposite side over adjacent side (TOA). Tan(angle) = opposite/adjacent

Since we know the length of the opposite (10m) and adjacent (300) sides, we can use the inverse tangent (tan-1) function on a calculator to get the value of the angle. 

tan-1(10/300)=1.90915... which rounds to 1.9 degrees, or 1 and 9/10 of a degree.

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3 years ago

Answered By Majid B

 $\theta=\tan^{-1}\left(\frac{10m}{300m}\right)=1.9^{\circ}$θ=tan1(10m300m )=1.9? 


3 years ago

Answered By Mahboubeh D

We have 300 (m) in length and 10 (m) in height which is equal to 30 (m) in length and 1 (m) in height.

so we can write:

Tan  $\alpha$α$\frac{1}{30}$130   $\rightarrow$  $\alpha=$α= Tan-1$\frac{1}{30}$130  )