When the polynomial 3y^3-4y^2+by+6 is divided by y+2, the remainder is -40
1 year ago
It looks like we have to find b :)
Based on the The Remainder Theorem:
If a polynomial f(x) is divided by x−a, the remainder is the constant f(a).
Here the a = -2, because y + 2 = y - (-2)
So, remainder would be:
R = f(-2) = 3(-2)3 - 4(-2)2 + b(-2) + 6 = -24 - 16 - 2b + 6 = -34 - 2b = -40
-2b = -6
b = 3
1 year ago
Answered By Majid B
It looks like we have to find b :)
Based on the The Remainder Theorem:
If a polynomial f(x) is divided by x−a, the remainder is the constant f(a).
Here the a = -2, because y + 2 = y - (-2)
So, remainder would be:
R = f(-2) = 3(-2)3 - 4(-2)2 + b(-2) + 6 = -24 - 16 - 2b + 6 = -34 - 2b = -40
-2b = -6
b = 3