A 55.0 kg crate is being pulled down a 20.0 $^{\circ}$^?  incline by a rope(acting parallel with the incline surface). If it is accelerating downwards at 1.50m/s $^2$²  and the force of the kinetic friction is 152 N then what is the tension of the rope?

5 years ago

Answered By James S

50 Newtons

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5 years ago

Answered By James S

F=F_f+ma-mgsin(20)=152+(55*1.5)-(55*9.81*sin(20))=50N

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