A 60.0-kg athlete jumps vertically upward
from the ground to a height of 0.910 m above
the ground. What was the athlete’s initial
It's physics grade 10 and I just don't know what formula to use or how to solve these
11 months ago
The initial velocity is the unknown, desired quantity. Perhaps the thing the realize is: the final velocity is 0, at the given displacement. So we have a vf , d, and a (is equal to g, the acceleration due to gravity), and we want to solve for vi.
The required equation is then:
vf2 = vi2 + 2ad
vi = square-root( 0-(2*(-9.81)0.91)
Note that the acceleration due to gravity is given a negative sign here, as it's opposing the initial velocity, slowing the athlete to 0 m/s at the maximum height.
Note that the mass of the athlete is not used to solve the problem; we are close to the Earth's surface, and the force of gravity is not varying in this problem, so the acceleration is constant.