Answered By Abdullah A

Work is just the energy inputed into the system. All you have to do it determine the kinetic energy change going from 10 to 30 m/s

W=KE=(1/2)m*v2^2-(1/2)*m*v1^2

W=KE= (1/2)*820kg*30^2 -(1/2)*820*10^2

W=KE=328 000 J

So 328 000 J energy needs to be put in.

Answered By Harsh P

Work = Force. Distance

Work = mass. Acceleration. Distance

Work = m.a.s.

Now, V_f² - V_i² = 2.a.s

So,

a.s= (V_f²- V_i²)/2.

Let's, Substitute this outcome in the formula of Work.

So,

Work = m.a.s = m.(V_f² - V_i²)/2

Work= 820×(30²-10²)×(1/2)= 328000 J

Answered By Emily D

GIVEN

m = 820 kg

vi = 10 m/s

vf = 30 m/s

EQUATIONS

W = Ef - Ei

Ek = 0.5mv^2

SOLUTION

Substitute our known mass and velocities into the kinetic energy equation and then into the work equation.

W = [0.5*820*30^2] - [0.5*820*10^2]

W = 328,000 J or 328 kJ