Given $
Y-k=a\
left(x-h\
right)^2$ Y−k=a(x−h)^{2} , a=1, h<0, k>0, which quadrant is the vertex in?

6 years ago

Answered By Qi (Jeff) J

Since h<0 which indicates a left shift So it has to be in quadrant 2 and 4

Then we have k>0 which means a upward shift so it has to be in quadrant 1 and 2.

Since quadrant 2 is the only quadrant that fits both criteria then quadrant 2 is the answer

5 years ago

Answered By Sujalakshmy V

The equation Y-k=a(x-h)^{2} can be written as Y=a(x-h)^{2}+k

The vertex of this equation is (h,k)

As it is given in the question, h<0, the x co-ordinate of the vertex will be in the quadrant 2 or 3.

Again as k>0, the y cordinate of the vertex will be in the quadrant 1 or 2.

Hence the vertex which matches two criteria will be a vertex in the quadrant 2.

So,Quadrant 2 is the answer.

4 years ago

Answered By Peter O

Y = a(x-h)2 + k, a = 1, h$<$<0 and k$>$>0

x - h = 0 $\rightarrow$→ x =h

Y = a(x-h)^{2} + k

= a(0)^{2} + k$\rightarrow$→ Y = k

The vertex of Y = a(x-h)^{2} + k is at (x=h, y=k) that is the coordinate (h,k) which is in the 2^{nd} Quadrant since h is in the negative x-axis and k is in positive y-axis.

6 years ago

## Answered By Qi (Jeff) J

Since h<0 which indicates a left shift So it has to be in quadrant 2 and 4

Then we have k>0 which means a upward shift so it has to be in quadrant 1 and 2.

Since quadrant 2 is the only quadrant that fits both criteria then quadrant 2 is the answer

5 years ago

## Answered By Sujalakshmy V

The equation Y-k=a(x-h)

^{2}can be written as Y=a(x-h)^{2}+kThe vertex of this equation is (h,k)

As it is given in the question, h<0, the x co-ordinate of the vertex will be in the quadrant 2 or 3.

Again as k>0, the y cordinate of the vertex will be in the quadrant 1 or 2.

Hence the vertex which matches two criteria will be a vertex in the quadrant 2.

So,Quadrant 2 is the answer.

4 years ago

## Answered By Peter O

Y = a(x-h)2 + k, a = 1, h$<$<0 and k$>$>0

x - h = 0 $\rightarrow$→ x =h

Y = a(x-h)

^{2}+ k= a(0)

^{2}+ k $\rightarrow$→ Y = kThe vertex of Y = a(x-h)

^{2}+ k is at (x=h, y=k) that is the coordinate (h,k) which is in the 2^{nd}Quadrant since h is in the negative x-axis and k is in positive y-axis.