If f(x)= x^{2}+4x+4, then the domain of y= 1/f(x) is?

2 years ago

Answered By Albert S

The domain is the set of all possible values of the independent variables. The independent variable is x. X can be anything => all real numbers.

2 years ago

Answered By Xuezhong J

f(x)=x^{2}+4x+4=(x+2)^{2 }>0 when x is a real number, so the domain of y=1/f(x) is all real numbers.

2 years ago

Answered By Albert S

The only trick part to this question is the possibility of dividing by zero which causes the function to be undefined. To determine when the denominater is zero factor the function so it becomes f(x) = (x+2)(x+2) the only instance where you divide by zero is when x+2=0 or x=-2. This could be considered a restriction on the domain but it is just a singularity in the range where the function approached infinity.

2 years ago

Answered By Xuezhong J

so the corret answer shall be: the domain of y =1/f(x) is all real numbers except -2.

2 years ago

Answered By Kazi A

In general, for any function f(x) which is defined over the entire domain of real numbers, then 1/f(x) is also defined for all real numbers x EXCEPT those x for which f(x) = 0. If f(x) = 0 has no solution, then the domain of 1/f(x) is all real numbers.

2 years ago

## Answered By Albert S

The domain is the set of all possible values of the independent variables. The independent variable is x. X can be anything => all real numbers.

2 years ago

## Answered By Xuezhong J

f(x)=x

^{2}+4x+4=(x+2)^{2 }>0 when x is a real number, so the domain of y=1/f(x) is all real numbers.2 years ago

## Answered By Albert S

The only trick part to this question is the possibility of dividing by zero which causes the function to be undefined. To determine when the denominater is zero factor the function so it becomes f(x) = (x+2)(x+2) the only instance where you divide by zero is when x+2=0 or x=-2. This could be considered a restriction on the domain but it is just a singularity in the range where the function approached infinity.

2 years ago

## Answered By Xuezhong J

so the corret answer shall be: the domain of y =1/f(x) is all real numbers except -2.

2 years ago

## Answered By Kazi A

In general, for any function f(x) which is defined over the entire domain of real numbers, then 1/f(x) is also defined for all real numbers x EXCEPT those x for which f(x) = 0. If f(x) = 0 has no solution, then the domain of 1/f(x) is all real numbers.