in mice, G for grey coat colour is dominant to g (black coat). The gg individuals are black. 2 grey mice are mated to produce 9 grey mice and 2 black mice. Explain the results
How do u anser this
3 years ago
Answered By Emily D
Punnett squares, and probabilities, my friend!
The offspring are:
9 grey (9/11 = 80% ish) can be GG, Gg, or gG
2 black (2/11 = 20% ish) can ONLY be gg
11 total
Since both parents can only pass on one gene and we need TWO copies of the recessive gene, both parents must carry the gene. Now the question is: are both parents grey (Gg and Gg) or is one purely black (Gg and gg)? So let's compare the two possible Punnett squares.
Looking at these squares, our probabilities match up closely with the "Two Grey Heterozygous" scenario. It could be crummy odds with a black mouse and a grey het mouse, but since we have to make a guess Gg x Gg is the most likely pairing.
Hope that helps! If it doesn't make sense, feel free to ask a follow-up question. I'll try to keep an eye on the help page just in case
3 years ago
Answered By Emily D
Punnett squares, and probabilities, my friend!
The offspring are:
9 grey (9/11 = 80% ish) can be GG, Gg, or gG
2 black (2/11 = 20% ish) can ONLY be gg
11 total
Since both parents can only pass on one gene and we need TWO copies of the recessive gene, both parents must carry the gene. Now the question is: are both parents grey (Gg and Gg) or is one purely black (Gg and gg)? So let's compare the two possible Punnett squares.
Looking at these squares, our probabilities match up closely with the "Two Grey Heterozygous" scenario. It could be crummy odds with a black mouse and a grey het mouse, but since we have to make a guess Gg x Gg is the most likely pairing.
Hope that helps! If it doesn't make sense, feel free to ask a follow-up question. I'll try to keep an eye on the help page just in case
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