Alberta Free Tutoring And Homework Help For Math 30-1

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Log125X=2/3

4 years ago

Answered By Suman G

 $\log_bX=Y$logbX=Y  is equivalent to X=bY.

According to this formula, in our case, X=1252/3 = (53)2/3 = 52 = 25

Hence, X =25


4 years ago

Answered By Mingrui (Mark) J

log Q = (ln b) / (ln Q)

log125 X = (ln X) / (ln 125) = 2 / 3

ln X = (2/3) * (ln 125) = ln (125 2/3 

1252/3 = (³√125) ² = 5² = 25

ln X = ln(125 2/3) = ln(25)

ln X = ln 25

X = 5

 

 

(you can use base-10 log which is just "log" instead of ln and that would work too)

 

:)

 


4 years ago

Answered By Mingrui (Mark) J

sorry, last post is x = 25 i meant


4 years ago

Answered By Daiwei L

 Since this logarithem form is difficult to work with, we change it to exponential. 

The exponential is an inverse of the logarithem function. Therefore, we swapthe x and y of (log125x = 2/3). 

Thus, we have 125 as the base, 2/3 as the power and we have 1252/3 = x.

We can then solve for x, 1252/3 = 5* (2/3) = 52 = 25 = x


4 years ago

Answered By Aleksandar B

The form y=bcan also be written as logb(y)=x

So log125(x)= 2/3 translates to x= 1252/3=(1252)1/3=25.


4 years ago

Answered By Jackie C

X=(125)2/3=[(125)1/3]2=[(5*5*5)1/3]2=(5)2=25