X-3 and x+1 are both factors of the polynomial mx3-4x2+nx-6. Determine the values for both m and n.
5 years ago
mx^3-4x^2+nx-6
set of equations:
-m-4-n-6=0
9m+n=14
The solution would be m=3 and n=-13
X=3 &x=-1 are solutions of equation mx^3-4x^2-nx-6
putting x=3 and x=-1in above equation
we get
27x-36+3n-6=0
on simplifying both these equations we get 9m+n=14
m+n=-10
further solving both these equations we get m=3 and n= -13
X = 3 and X = -1 are solutions to polynomial: mX3-4x2+nx-6 = 0,solving for X = 327*m - (4*9) + (n*3) - 6 = 0, hence, 27m+3n=42, 9m+n = 14solving for X = -1(-1*m) - (4*1) + (n*-1) - 6 = 0, hence, -m-n= 10, m+n = -109m+n = 14, and m+n = -10, subtracting two equations, 8m = 24, hence m =3, n = -10-m = -10-3 = -13then, m=3, n=-13
5 years ago
Answered By Mohsen F
mx^3-4x^2+nx-6
set of equations:
-m-4-n-6=0
9m+n=14
The solution would be m=3 and n=-13
5 years ago
Answered By Gazalpreet S
X=3 &x=-1 are solutions of equation mx^3-4x^2-nx-6
putting x=3 and x=-1in above equation
we get
27x-36+3n-6=0
-m-4-n-6=0
on simplifying both these equations we get 9m+n=14
m+n=-10
further solving both these equations we get m=3 and n= -13
5 years ago
Answered By Mohamed H
X = 3 and X = -1 are solutions to polynomial: mX3-4x2+nx-6 = 0,solving for X = 327*m - (4*9) + (n*3) - 6 = 0, hence, 27m+3n=42, 9m+n = 14solving for X = -1(-1*m) - (4*1) + (n*-1) - 6 = 0, hence, -m-n= 10, m+n = -109m+n = 14, and m+n = -10, subtracting two equations, 8m = 24, hence m =3, n = -10-m = -10-3 = -13then, m=3, n=-13