Describe how the graph sketch on the previous page would be different if
i. s=3
ii. s=0
6 years ago
Answered By Peter O
y=(x-2)(x-s), s=-4
=x2 +2x -8
(i) y=(x-2)(x-s), s=3
=x2 -5x +6
(ii) y=(x-2)(x-s), s=0
x2 -2x
From the three graphs, we can see that there is a point that satisfied these quadratic expressions and that is point(2,0). Even though each expression has two solutions, one of the solution to each of them is Point(2,0), ie x=2 and y=0.
6 years ago
Answered By Peter O
y=(x-2)(x-s), s=-4
=x2 +2x -8
(i) y=(x-2)(x-s), s=3
=x2 -5x +6
(ii) y=(x-2)(x-s), s=0
x2 -2x
From the three graphs, we can see that there is a point that satisfied these quadratic expressions and that is point(2,0). Even though each expression has two solutions, one of the solution to each of them is Point(2,0), ie x=2 and y=0.
Attached Graph: