The coefficient of friction for a lawn mower moving over grass is 0.81 what force is required to accelerate the 12kg mass of the lawn mower to 1.25m/s from rest in 3.0 seconds?
4 years ago
from the problem we see
initial velocity(u)= 0;
therefore from the formula v = u + at;
we find accelaration
1.25 = 0 + a(3);
we know that F = m*a;
F = 12*0.4166;
F= 5 N;
however this is the normal force.
Ff = Fn/0.81(frictional coefficient)
FF=5/0.81= 6.17 N;
therefore you need a force of 6.17 newtons.