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a bag has 3 red tiles, 1 yellow tile and 2 green tiles 



b) how does the value change if the first tile is not replaced? 

1 year ago

Answered By Emily D

It looks like you cut out part A because you understood it, but that means I'm not quite sure what the context of "how does the value change" is.

Odds of picking two red tiles: the first one is  $\frac{3}{6}$36   (0.5) and the second one is  $\frac{\left(3-1\right)}{\left(6-1\right)}=\frac{2}{5}$(31)(61) =25  (0.4). The odds in favour decrease because the ratio of red tiles to other tiles has decreased.

Odds of picking a red tile and then a yellow tile: red tile is still 0.5 but the yellow tile is   $\frac{1}{\left(6-1\right)}=\frac{1}{5}$1(61) =15  (0.2) now instead of   $\frac{1}{6}$16  (0.167). The odds in favour increase because the ratio of yellow tiles to other tiles has increased.

Odds of picking a red tile and then a green tile will change the same way the red/yellow combination did.