a bag has 3 red tiles, 1 yellow tile and 2 green tiles
b) how does the value change if the first tile is not replaced?
4 years ago
Answered By Emily D
It looks like you cut out part A because you understood it, but that means I'm not quite sure what the context of "how does the value change" is.
Odds of picking two red tiles: the first one is $\frac{3}{6}$36 (0.5) and the second one is $\frac{\left(3-1\right)}{\left(6-1\right)}=\frac{2}{5}$(3−1)(6−1)=25 (0.4). The odds in favour decrease because the ratio of red tiles to other tiles has decreased.
Odds of picking a red tile and then a yellow tile: red tile is still 0.5 but the yellow tile is $\frac{1}{\left(6-1\right)}=\frac{1}{5}$1(6−1)=15 (0.2) now instead of $\frac{1}{6}$16 (0.167). The odds in favour increase because the ratio of yellow tiles to other tiles has increased.
Odds of picking a red tile and then a green tile will change the same way the red/yellow combination did.
4 years ago
Answered By Emily D
It looks like you cut out part A because you understood it, but that means I'm not quite sure what the context of "how does the value change" is.
Odds of picking two red tiles: the first one is $\frac{3}{6}$36 (0.5) and the second one is $\frac{\left(3-1\right)}{\left(6-1\right)}=\frac{2}{5}$(3−1)(6−1) =25 (0.4). The odds in favour decrease because the ratio of red tiles to other tiles has decreased.
Odds of picking a red tile and then a yellow tile: red tile is still 0.5 but the yellow tile is $\frac{1}{\left(6-1\right)}=\frac{1}{5}$1(6−1) =15 (0.2) now instead of $\frac{1}{6}$16 (0.167). The odds in favour increase because the ratio of yellow tiles to other tiles has increased.
Odds of picking a red tile and then a green tile will change the same way the red/yellow combination did.