A student decides to go hiking. First, he walks 6.0 km [E] in 2.0 h, then he walks 8.0 km [N] in 4.0 h. Because he is tired, he takes the bus home. Calculate his average velocity while walking. [10]
2 years ago
Answered By Leonardo F
We have to remember that average velocity is the ratio between the displacement and the time elapsed. The displacement is calculated by considering only the difference between the final and initial positions. So, in our case, we have a right triangle, whose legs are 6 and 8 km. So, calculating the hypothenuse by using the Pythagorean theorem:
2 years ago
Answered By Leonardo F
We have to remember that average velocity is the ratio between the displacement and the time elapsed. The displacement is calculated by considering only the difference between the final and initial positions. So, in our case, we have a right triangle, whose legs are 6 and 8 km. So, calculating the hypothenuse by using the Pythagorean theorem:
x^2 = 6^2 + 8^2
x^2 = 100
x = 10 km
So the average velocity will be:
v = 10 km / 6 h = 1.67 km/h