The probability of A and B occurring is equal to the probability of A multiplied by the probability of B. In this case, you want the SAME number on both dice - but the number on the first die doesn't matter since we only care that they match.

So the probability die A rolls a number we want is $\frac{6}{6}$66 and the probability die B will match is $\frac{1}{6}$16 meaning the odds of rolling doubles is $\frac{1}{1}\times\frac{1}{6}=\frac{1}{6}$11×16=16

3 years ago

## Answered By Emily D

I'm assuming backgammon uses two 6-sided dice

$P\left(A\text{∩}B\right)=P\left(A\right)\times P\left(B\right)$P(A∩B)=P(A)×P(B)

The probability of A and B occurring is equal to the probability of A multiplied by the probability of B. In this case, you want the SAME number on both dice - but the number on the first die doesn't matter since we only care that they match.

So the probability die A rolls a number we want is $\frac{6}{6}$66 and the probability die B will match is $\frac{1}{6}$16 meaning the odds of rolling doubles is $\frac{1}{1}\times\frac{1}{6}=\frac{1}{6}$11 ×16 =16