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In the game backgammon, when you roll doubles with two dice you can double the total on the dice. what is the probability of rolling doubles

1 year ago

$P\left(A\text{∩}B\right)=P\left(A\right)\times P\left(B\right)$P(AB)=P(A)×P(B)
So the probability die A rolls a number we want is  $\frac{6}{6}$66   and the probability die B will match is  $\frac{1}{6}$16  meaning the odds of rolling doubles is   $\frac{1}{1}\times\frac{1}{6}=\frac{1}{6}$11 ×16 =16