## Alberta Free Tutoring And Homework Help For Math 10C

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### Given that cosB=0.4612,, what is the value of B to the nearest of a degree?

5 years ago 5 years ago In your calculator,  put cos-1 (0.4612)  you will get 62.5 degree ~63 degrees.  That's it.

5 years ago cos B = 0.4612

B = cos ^(-1) 0.4612

B = 62.54 degrees

5 years ago note that cos ^ (-1) = cos-1

5 years ago cos B = 0.4612

B = Arcos(0.4612)

B = 62.54 degrees

5 years ago So for this you're given the value or output of the function cosb=o.4612 like f(x)=y now in order to solve for x or in this case b you need to use the inverse of the function; cos-1 which in this case is also a function, it takes the output value and gives you your input!

So cos-10.4612=62.45

5 years ago Given  $\cos B=0.4612$cosB=0.4612

we can use the function arccos, or inverse cosine, to find the angle.

This appears as  $\cos^{-1}$cos1 on your calculator.

Apply to both sides

$\cos^{-1}\cos B=\cos^{-1}0.4612$cos1cosB=cos10.4612

$\cos^{-1}\cos B=B$cos1cosB=B

$\cos^{-1}0.4612=62.5º$cos10.4612=62.5º

To the nearest degree we get 63º